(3b^2-4b+2)(b-5)=

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Solution for (3b^2-4b+2)(b-5)= equation: 


Simplifying
(3b2 + -4b + 2)(b + -5) = 0

Reorder the terms:
(2 + -4b + 3b2)(b + -5) = 0

Reorder the terms:
(2 + -4b + 3b2)(-5 + b) = 0

Multiply (2 + -4b + 3b2) * (-5 + b)
(2(-5 + b) + -4b * (-5 + b) + 3b2 * (-5 + b)) = 0
((-5 * 2 + b * 2) + -4b * (-5 + b) + 3b2 * (-5 + b)) = 0
((-10 + 2b) + -4b * (-5 + b) + 3b2 * (-5 + b)) = 0
(-10 + 2b + (-5 * -4b + b * -4b) + 3b2 * (-5 + b)) = 0
(-10 + 2b + (20b + -4b2) + 3b2 * (-5 + b)) = 0
(-10 + 2b + 20b + -4b2 + (-5 * 3b2 + b * 3b2)) = 0
(-10 + 2b + 20b + -4b2 + (-15b2 + 3b3)) = 0

Combine like terms: 2b + 20b = 22b
(-10 + 22b + -4b2 + -15b2 + 3b3) = 0

Combine like terms: -4b2 + -15b2 = -19b2
(-10 + 22b + -19b2 + 3b3) = 0

Solving
-10 + 22b + -19b2 + 3b3 = 0

Solving for variable 'b'.

The solution to this equation could not be determined.

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